From: tchannel1@............

Date: Thu, 13 Mar 2008 10:28:52 -0600

Good question, and here's what I found: I had this issue on the copper = vertical, the bottom hinge is where I tried to use a roller on roller, = then I tried a foil hinge. Both failed big time. Because of the forces and the different angles of = pressure, the roller on roller keep sliding off. I resolved this using = the eyebolts, where that force or forces were retain as the rotation = change and the resulting angles. Since the roller was retained inside a = eyebolt its contact point just move around the eyebolt finding a new = spot on which to pivot. Not to suggest you should use eyebolts, but they worked for me, but = doing this may show you where the roller on roller need to be located. As to you question, I think all the factors would change the roller on = roller locations and angles, A, B, C and all the angles, change one and = the roller would need to be in a different location and or angle or it = would slide off. Thats why if the roller was mounted on a swivel, it = could be rotated in all directions until the apposing roller would not = slide off. ----- Original Message -----=20 From: Jerry Payton=20 To: PSN-L=20 Sent: Thursday, March 13, 2008 8:55 AM Subject: Question Please Hopefully, I can frame this question understandably. In our standard garden-gate configuration: Consider a traditional = right triangle with side A (vertical) & B (base) with hypotenuse C. If = a mass is attached to the BC end, I assume that there is an applied = force to keep point AB against the pivot, whichever method is used = there. My question is, "Does it matter what the angle of the hypotenuse is? = Would, say a 30 degree angle work as well as a 45 degrees, or is there a = cutoff angle to maintain the horizontal force against the pivot?" This could directly affect the height of A when constructing a Lehman. = Of course, I think I remember (its bee a long time!)that an equilateral = triangle is more stable. Therefore, I assume it might depend upon the = length of the arm (BC). Regards, and "thinking too much"Good question, and here's what I = found: =20 I had this issue on the copper vertical, the bottom hinge is where I = tried to=20 use a roller on roller, then I tried a foil hinge.Both failed big time. Because of = the forces=20 and the different angles of pressure, the roller on roller keep sliding = off. I=20 resolved this using the eyebolts, where that force or forces were retain = as the=20 rotation change and the resulting angles. Since the roller was = retained=20 inside a eyebolt its contact point just move around the eyebolt finding = a new=20 spot on which to pivot.Not to suggest you should use eyebolts, = but they=20 worked for me, but doing this may show you where the roller on roller = need to be=20 located.As to you question, I think all the = factors would=20 change the roller on roller locations and angles, A, B, C and all the = angles,=20 change one and the roller would need to be in a different location and = or angle=20 or it would slide off. Thats why if the roller was mounted = on a=20 swivel, it could be rotated in all directions until the apposing roller = would=20 not slide off.----- Original Message -----From:=20 Jerry = Payton=20To:PSN-LSent:Thursday, March 13, 2008 = 8:55=20 AMSubject:Question PleaseHopefully, I can frame this question understandably.In our standard garden-gate configuration: = Consider a=20 traditional right triangle with side A (vertical) & B=20 (base) with hypotenuse C. If a mass is attached to the BC = end, I=20 assume that there is an applied force to keep point AB against = the=20 pivot, whichever method is used there.My question is, "Does it matter what the angle of the hypotenuse=20 is? Would, say a 30 degree angle work as well as a 45 degrees, = or is=20 there a cutoff angle to maintain the horizontal force against the=20 pivot?"This could directly affect the height of A when constructing = a=20 Lehman. Of course, I think I remember (its bee a long time!)that = an=20 equilateral triangle is more stable. Therefore, I assume it = might=20 depend upon the length of the arm (BC).Regards, and "thinking too much"Jerry