PSN-L Email List Message
Subject: Re: Is a Lehman geometry rolling pivot inherently unstable?
From: Brett Nordgren Brett3nt@.............
Date: Sun, 06 Jul 2008 06:56:24 -0400
It was +/- 0.00043" over 10 degrees.
A quick and dirty attempt to plot out the locus for your rolling ball case
using a CAD program gives some interesting results. They suggest that a
rolling pivot may be generating a perfectly circular locus for the end (or
any other point) of the beam. I seem to remember seeing a proof of that
somewhere, though I'm not sure. The way the locus radius varies with the
length of the beam is somewhat interesting. Obviously for a very long beam
the radius becomes large, but if you choose a point on the beam close to
the center of the pivot ball, the radius also becomes large. So for any
selected pivot ball diameter, there should be a beam length which has a
minimum radius for its locus.....interesting.
I tried a 1"dia ball with a 5" long beam, and over a motion of +/- 5
degrees, the end traced a circle of radius of 6.0494935" +/-
0.0000001" which was the limit of the accuracy of my CAD program. That
suggests that an analytical approach is worth looking into, to prove that
it is indeed a perfect circle (if it is) and to come up with an expression
to locate the center. In the extreme example above, I think if you located
the plate approximately 0.5494935" forward from a point directly under the
upper wire attachment you would obtain the circular motion you were looking
I am now starting to think that it's not going to be a geometrically
perfect circle. If you try a 1/2" long beam with a 1" dia ball, you get a
At 10:49 PM 7/5/2008 -0700, you wrote:
>It would seem me, too, that the figure-8 pivot is very similar to a ball
>on a plate except that the figure-8 pivot would have about twice the
>effect due to the point of contact moving along a second curved
>surface adding to the effective pivot point movement. One quick
>observation -- you say, "...traced out a circle, accurate to +/- 0.00043"
>or 43 microinches per degree."
But 0.00043" is 430 microinches, not 43 microinches and in my brief
conjecture, 100 microinches is enough to lead to failure of the swing
trajectory in a 20 second period Lehman.
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